나이트의 이동 (7562번)
https://www.acmicpc.net/problem/7562
풀이방법
- 전형적인 BFS 문제이다.
- X, Y가 움직일 수 있는 모든 경우의 수 8가지를 이용해 문제를 해결한다.
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import java.io.IOException;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.LinkedList;
import java.util.Queue;
import java.util.StringTokenizer;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
int T = Integer.parseInt(br.readLine());
StringTokenizer st;
int I = 0;
StringBuilder sb = new StringBuilder();
while (T-- > 0) {
I = Integer.parseInt(br.readLine());
int[] curPos = new int[2];
st = new StringTokenizer(br.readLine());
curPos[0] = Integer.parseInt(st.nextToken());
curPos[1] = Integer.parseInt(st.nextToken());
st = new StringTokenizer(br.readLine());
int[] targetPos = new int[2];
targetPos[0] = Integer.parseInt(st.nextToken());
targetPos[1] = Integer.parseInt(st.nextToken());
int[][] dist = new int[I+1][I+1];
initDist(dist);
if (curPos[0] == targetPos[0] && curPos[1] == targetPos[1]) {
sb.append(0).append('\n');
} else {
bfs(dist, curPos, targetPos, I);
sb.append(dist[targetPos[1]][targetPos[0]]).append('\n');
}
}
System.out.println(sb);
}
private static void initDist(int[][] dist) {
for(int i=0; i<dist.length; i++) {
for (int j=0; j<dist.length; j++) {
dist[i][j] = -1;
}
}
}
private static void bfs(int[][] dist, int[] curPos, int[] targetPos, int I) {
Queue<int[]> queue = new LinkedList<>();
queue.add(curPos);
dist[curPos[1]][curPos[0]] = 0;
int[] cur;
int[] xPos = {-1, -1, 1, 1, -2, -2, 2, 2};
int[] yPos = {2, -2, 2, -2, 1, -1, 1, -1};
int dx = 0; int dy = 0;
while (!queue.isEmpty()) {
cur = queue.poll();
for(int i=0; i<8; i++) {
dx = cur[0] + xPos[i];
dy = cur[1] + yPos[i];
if (dx < 0 || dx >= I || dy < 0 || dy >= I) continue;
if (dist[dy][dx] != -1) continue;
dist[dy][dx] = dist[cur[1]][cur[0]] + 1;
if (dx == targetPos[0] && dy == targetPos[1]) return;
queue.add(new int[] { dx, dy });
}
}
}
}
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